AEW Fight Forever How to Unlock Brodie Lee

AEW Fight Forever has followed the traditional method of allowing players to find their own secret moves, plots, and personalities. While this is a fantastic homage to wrestling games of yore, some players may lack the patience required to discover.

How to unlock Owen Hart, Brodie Lee, and Paul Wight in AEW Fight Forever in the days of Accelerator Packs unlocking everything at once in WWE 2K23.

It’s intended to keep fans engaging and provide replay value by requiring gamers to play the wrestling game frequently. However, this tutorial will detail the most effective ways to unlock all three characters.

AEW Fight Forever guide
Image Credit: THQ Nordic

How to unlock Brodie Lee in AEW Fight Forever

In AEW Fight Forever, there is just one way to unleash Brodie Lee: beat him. As a result, you’ll need to start a tale about the Dark Order. If you follow the instructions below, you should be able to locate Brodie Lee:

  • Start a new Road to Elite playthrough.
  • Complete the first chapter with a few losses and victories. For example, you can try to win the Battle Royal match in Prologue but lose to MJF.
  • The storyline that you need to trigger is called “Block 2B – Join The Dark Order”. It seems that Cody Rhodes, Sammy Guevara, and Britt Baker are able to increase your chances of getting this exact block.
  • If the Dark Order storyline is triggered, John Silver will ask you to join the Dark Order. You can say “yes” or “no” and then continue your playthrough.
  • At the end of this storyline, you will have to fight Brodie Lee.
  • Defeat him.
  • After that, Brodie Lee will be available in the shop. You will be able to buy him for 30,000 Credits.
Also Read  AEW Fight Forever How to Unlock Owen Hart

Brodie Lee is not a challenging boss, and he can be found in the second chapter. So, even if you fail, you’ll be able to restart the game and find yourself back in front of him in no time.

So that’s how to get Brodie Lee in AEW Fight Forever as I’ll see you in the next guide.